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        1. Sn為數(shù)列{dn}的前n項(xiàng)和.Sn=.又Hn為數(shù)列{Sn}的調(diào)和平均數(shù). 查看更多

           

          題目列表(包括答案和解析)

          由函數(shù)y=f(x)確定數(shù)列{an},an=f(n),函數(shù)y=f(x)的反函數(shù)y=f-1(x)能確定數(shù)列{bn},bn=f-1(n),若對(duì)于任意n?N*,都有bn=an,則稱數(shù)列{bn}是數(shù)列{an}的“自反數(shù)列”.
          (1)若函數(shù)f(x)=
          px+1
          x+1
          確定數(shù)列{an}的自反數(shù)列為{bn},求an;
          (2)在(1)條件下,記
          n
          1
          x1
          +
          1
          x2
          +…
          1
          xn
          為正數(shù)數(shù)列{xn}的調(diào)和平均數(shù),若dn=
          2
          an+1
          -1
          ,Sn為數(shù)列{dn}的前n項(xiàng)之和,Hn為數(shù)列{Sn}的調(diào)和平均數(shù),求
          lim
          n→∞
          =
          Hn
          n
          ;
          (3)已知正數(shù)數(shù)列{cn}的前n項(xiàng)之和Tn=
          1
          2
          (Cn+
          n
          Cn
          )
          .求Tn表達(dá)式.

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          由函數(shù)y=f(x)確定數(shù)列{an},an=f(n),函數(shù)y=f(x)的反函數(shù)y=f-1(x)能確定數(shù)列{bn},bn=f-1(n),若對(duì)于任意nÎN*,都有bn=an,則稱數(shù)列{bn}是數(shù)列{an}的“自反數(shù)列”.
          (1)若函數(shù)f(x)=確定數(shù)列{an}的自反數(shù)列為{bn},求an;
          (2)在(1)條件下,記為正數(shù)數(shù)列{xn}的調(diào)和平均數(shù),若dn=,Sn為數(shù)列{dn}的前n項(xiàng)之和,Hn為數(shù)列{Sn}的調(diào)和平均數(shù),求;
          (3)已知正數(shù)數(shù)列{cn}的前n項(xiàng)之和.求Tn表達(dá)式.

          查看答案和解析>>

                     由函數(shù)y=f(x)確定數(shù)列{an},an=f(n),函數(shù)y=f(x)的反函數(shù)y=f –1(x)能確定數(shù)列{bn},bn= f –1(n),若對(duì)于任意nÎN*,都有bn=an,則稱數(shù)列{bn}是數(shù)列{an}的“自反數(shù)列”.

             (1)若函數(shù)f(x)=確定數(shù)列{an}的自反數(shù)列為{bn},求an;

             (2)在(1)條件下,記為正數(shù)數(shù)列{xn}的調(diào)和平均數(shù),若dn=,Sn為數(shù)列{dn}的前n項(xiàng)之和,Hn為數(shù)列{Sn}的調(diào)和平均數(shù),求;

             (3)已知正數(shù)數(shù)列{cn}的前n項(xiàng)之和 求Tn表達(dá)式.

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          由函數(shù)y=f(x)確定數(shù)列{an},an=f(n),函數(shù)y=f(x)的反函數(shù)y=f-1(x)能確定數(shù)列{bn},bn=f-1(n),若對(duì)于任意nÎN*,都有bn=an,則稱數(shù)列{bn}是數(shù)列{an}的“自反數(shù)列”.
          (1)若函數(shù)f(x)=確定數(shù)列{an}的自反數(shù)列為{bn},求an;
          (2)在(1)條件下,記為正數(shù)數(shù)列{xn}的調(diào)和平均數(shù),若dn=,Sn為數(shù)列{dn}的前n項(xiàng)之和,Hn為數(shù)列{Sn}的調(diào)和平均數(shù),求;
          (3)已知正數(shù)數(shù)列{cn}的前n項(xiàng)之和.求Tn表達(dá)式.

          查看答案和解析>>

          由函數(shù)y=f(x)確定數(shù)列{an},an=f(n),函數(shù)y=f(x)的反函數(shù)y=f-1(x)能確定數(shù)列{bn},bn=f-1(n),若對(duì)于任意nÎN*,都有bn=an,則稱數(shù)列{bn}是數(shù)列{an}的“自反數(shù)列”.
          (1)若函數(shù)f(x)=確定數(shù)列{an}的自反數(shù)列為{bn},求an;
          (2)在(1)條件下,記為正數(shù)數(shù)列{xn}的調(diào)和平均數(shù),若dn=,Sn為數(shù)列{dn}的前n項(xiàng)之和,Hn為數(shù)列{Sn}的調(diào)和平均數(shù),求;
          (3)已知正數(shù)數(shù)列{cn}的前n項(xiàng)之和.求Tn表達(dá)式.

          查看答案和解析>>


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