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        1. 當(dāng)x>0時(shí)..∴.∴ 查看更多

           

          題目列表(包括答案和解析)

          設(shè),對(duì)任意實(shí)數(shù)t,記

          (Ⅰ)求函數(shù)y=f(x)-g2(x)的單調(diào)區(qū)間;

          (Ⅱ)求證:(ⅰ)當(dāng)x>0時(shí),f(x)gf(x)≥g2(x)對(duì)任意正實(shí)數(shù)t成立;

          (Ⅲ)有且僅有一個(gè)正實(shí)數(shù)x0,使得gx(x0)≥gt(x0)對(duì)任意正實(shí)數(shù)t成立.

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          設(shè),對(duì)任意實(shí)數(shù)t,記
          (I)求函數(shù)y=f(x)-g8(x)的單調(diào)區(qū)間;
          (II)求證:(ⅰ)當(dāng)x>0時(shí),f(x)≥gt(x)對(duì)任意正實(shí)數(shù)t成立;
          (ⅱ)有且僅有一個(gè)正實(shí)數(shù)x,使得g8(x)≥gt(x)對(duì)任意正實(shí)數(shù)t成立.

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          設(shè)f(x)=,對(duì)任意實(shí)數(shù)t,記gt(x)=x-t.

          (Ⅰ)求函數(shù)y=f(x)-g8(x)的單調(diào)區(qū)間;

          (Ⅱ)求證:(1)當(dāng)x>0時(shí),f(x)≥gt(x)對(duì)任意正實(shí)數(shù)t成立;

          (2)有且僅有一個(gè)正實(shí)數(shù)x0,使得g8(x0)≥gt(x0)對(duì)任意正實(shí)數(shù)t成立.

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          設(shè)f(x)=
          x3
          3
          ,對(duì)任意實(shí)數(shù)t,記gt(x)=t
          2
          3
          x-
          2
          3
          t

          (Ⅰ)求函數(shù)y=f(x)-g8(x)的單調(diào)區(qū)間;
          (Ⅱ)求證:(ⅰ)當(dāng)x>0時(shí),f(x)≥gt(x)對(duì)任意正實(shí)數(shù)t成立;
          (ⅱ)有且僅有一個(gè)正實(shí)數(shù)x0,使得g8(x0)≥gt(x0)對(duì)任意正實(shí)數(shù)t成立.

          查看答案和解析>>

          設(shè)f(x)=
          x3
          3
          ,對(duì)任意實(shí)數(shù)t,記gt(x)=t
          2
          3
          x-
          2
          3
          t

          (I)求函數(shù)y=f(x)-g8(x)的單調(diào)區(qū)間;
          (II)求證:(。┊(dāng)x>0時(shí),f(x)≥gt(x)對(duì)任意正實(shí)數(shù)t成立;
          (ⅱ)有且僅有一個(gè)正實(shí)數(shù)x0,使得g8(x0)≥gt(x0)對(duì)任意正實(shí)數(shù)t成立.

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