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        1. 一個(gè)空間幾何體的三視圖及部分?jǐn)?shù)據(jù)如圖所示.則這個(gè)幾何體的體積是 查看更多

           

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          精英家教網(wǎng)一個(gè)空間幾何體的三視圖及部分?jǐn)?shù)據(jù)如圖所示,則這個(gè)幾何體的體積是( 。
          A、3
          B、
          5
          2
          C、2
          D、
          3
          2

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          精英家教網(wǎng)一個(gè)空間幾何體的三視圖及部分?jǐn)?shù)據(jù)如右圖所示,則這個(gè)幾何體的體積是
           

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          一個(gè)空間幾何體的三視圖及部分?jǐn)?shù)據(jù)如圖所示(單位cm),則這個(gè)幾何體的體積是( 。

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          一個(gè)空間幾何體的三視圖及部分?jǐn)?shù)據(jù)如圖所示(單位:cm),則這個(gè)幾何體的表面積是
          24π
          24π
          cm2

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          精英家教網(wǎng)一個(gè)空間幾何體的三視圖及部分?jǐn)?shù)據(jù)如圖所示(單位:cm),則這個(gè)幾何體的體積是( 。
          A、3cm3
          B、
          5
          2
          cm3
          C、2cm3
          D、
          3
          2
          cm3

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          1-10.CDBBA   CACBD

          11.6ec8aac122bd4f6e 12. ①③④   13.-2或1  14. 6ec8aac122bd4f6e、6ec8aac122bd4f6e  15.2  16. 6ec8aac122bd4f6e 17.6ec8aac122bd4f6e.

          18.

          解:(1)由已知6ec8aac122bd4f6e6ec8aac122bd4f6e          7分

          (2)由6ec8aac122bd4f6e                                                                   10分

          由余弦定理得6ec8aac122bd4f6e                          14分

           

          19.(1)證明:∵PA⊥底面ABCD,BC6ec8aac122bd4f6e平面AC,∴PA⊥BC,                                  3分

          ∵∠ACB=90°,∴BC⊥AC,又PA∩AC=A,∴BC⊥平面PAC.                             5分

          (2)解:過(guò)C作CE⊥AB于E,連接PE,

          ∵PA⊥底面ABCD,∴CE⊥面PAB,

          ∴直線PC與平面PAB所成的角為6ec8aac122bd4f6e,                                                     10分

          ∵AD=CD=1,∠ADC=60°,∴AC=1,PC=2,

          6ec8aac122bd4f6e中求得CE=6ec8aac122bd4f6e,∴6ec8aac122bd4f6e.                                                  14分

           

          6ec8aac122bd4f6e20.解:(1)由6ec8aac122bd4f6e①,得6ec8aac122bd4f6e②,

          ②-①得:6ec8aac122bd4f6e.                              4分

          (2)由6ec8aac122bd4f6e求得6ec8aac122bd4f6e.          7分

          6ec8aac122bd4f6e6ec8aac122bd4f6e   11分

          6ec8aac122bd4f6e

          6ec8aac122bd4f6e.                                                                 14分

           

          21.解:

          (1)由6ec8aac122bd4f6e得c=1                                                                                       1分

          6ec8aac122bd4f6e,                                                         4分

          6ec8aac122bd4f6e6ec8aac122bd4f6e

          6ec8aac122bd4f6e                                                                                        5分

          (2)6ec8aac122bd4f6e6ec8aac122bd4f6e,6ec8aac122bd4f6e時(shí)取得極值.由6ec8aac122bd4f6e6ec8aac122bd4f6e6ec8aac122bd4f6e6ec8aac122bd4f6e.                                                                                          8分

          6ec8aac122bd4f6e,6ec8aac122bd4f6e,∴當(dāng)6ec8aac122bd4f6e時(shí),6ec8aac122bd4f6e

          6ec8aac122bd4f6e6ec8aac122bd4f6e上遞減.                                                                                       12分

          6ec8aac122bd4f6e∴函數(shù)6ec8aac122bd4f6e的零點(diǎn)有且僅有1個(gè)     15分

           

          22.解:(1) 設(shè)6ec8aac122bd4f6e,由已知6ec8aac122bd4f6e

          6ec8aac122bd4f6e,                                        2分

          設(shè)直線PB與圓M切于點(diǎn)A,6ec8aac122bd4f6e

          6ec8aac122bd4f6e,

          6ec8aac122bd4f6e6ec8aac122bd4f6e                                                 6分

          (2) 6ec8aac122bd4f6e點(diǎn) B(0,t),點(diǎn)6ec8aac122bd4f6e,                                                                7分

          進(jìn)一步可得兩條切線方程為:

          6ec8aac122bd4f6e,                                   9分

          6ec8aac122bd4f6e6ec8aac122bd4f6e,6ec8aac122bd4f6e,

          6ec8aac122bd4f6e,6ec8aac122bd4f6e,                                          13分

          6ec8aac122bd4f6e,又6ec8aac122bd4f6e時(shí),6ec8aac122bd4f6e

          6ec8aac122bd4f6e6ec8aac122bd4f6e面積的最小值為6ec8aac122bd4f6e                                                                            15分

           

           


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