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        1. 現(xiàn)要完成下列3項(xiàng)抽樣調(diào)查:①從10盒酸奶中抽取3盒進(jìn)行食品衛(wèi)生檢查.②科技報(bào)告廳有32排.每排有40個(gè)座位.有一次報(bào)告會(huì)恰好坐滿了聽眾.報(bào)告會(huì)結(jié)束后.為了聽取意見.需要請(qǐng)32名聽眾進(jìn)行座談.③東方中學(xué)共有160名教職工.其中一般教師120名.行政人員16名.后勤人員24名.為了了解教職工對(duì)學(xué)校在校務(wù)公開方面的意見.擬抽取一個(gè)容量為20的樣本.較為合理的抽樣方法是 (A)①簡(jiǎn)單隨機(jī)抽樣,②系統(tǒng)抽樣,③分層抽樣.(B)①簡(jiǎn)單隨機(jī)抽樣,②分層抽樣,③系統(tǒng)抽樣.(C)①系統(tǒng)抽樣,②簡(jiǎn)單隨機(jī)抽樣,③分層抽樣.(D)①分層抽樣,②系統(tǒng)抽樣,③簡(jiǎn)單隨機(jī)抽樣. 查看更多

           

          題目列表(包括答案和解析)

          1-10.CDBBA   CACBD

          11.6ec8aac122bd4f6e 12. ①③④   13.-2或1  14. 6ec8aac122bd4f6e、6ec8aac122bd4f6e  15.2  16. 6ec8aac122bd4f6e 17.6ec8aac122bd4f6e.

          18.

          解:(1)由已知6ec8aac122bd4f6e6ec8aac122bd4f6e          7分

          (2)由6ec8aac122bd4f6e                                                                   10分

          由余弦定理得6ec8aac122bd4f6e                          14分

           

          19.(1)證明:∵PA⊥底面ABCD,BC6ec8aac122bd4f6e平面AC,∴PA⊥BC,                                  3分

          ∵∠ACB=90°,∴BC⊥AC,又PA∩AC=A,∴BC⊥平面PAC.                             5分

          (2)解:過C作CE⊥AB于E,連接PE,

          ∵PA⊥底面ABCD,∴CE⊥面PAB,

          ∴直線PC與平面PAB所成的角為6ec8aac122bd4f6e,                                                     10分

          ∵AD=CD=1,∠ADC=60°,∴AC=1,PC=2,

          6ec8aac122bd4f6e中求得CE=6ec8aac122bd4f6e,∴6ec8aac122bd4f6e.                                                  14分

           

          6ec8aac122bd4f6e20.解:(1)由6ec8aac122bd4f6e①,得6ec8aac122bd4f6e②,

          ②-①得:6ec8aac122bd4f6e.                              4分

          (2)由6ec8aac122bd4f6e求得6ec8aac122bd4f6e.          7分

          6ec8aac122bd4f6e,6ec8aac122bd4f6e   11分

          6ec8aac122bd4f6e

          6ec8aac122bd4f6e.                                                                 14分

           

          21.解:

          (1)由6ec8aac122bd4f6e得c=1                                                                                       1分

          6ec8aac122bd4f6e,                                                         4分

          6ec8aac122bd4f6e6ec8aac122bd4f6e

          6ec8aac122bd4f6e                                                                                        5分

          (2)6ec8aac122bd4f6e6ec8aac122bd4f6e6ec8aac122bd4f6e時(shí)取得極值.由6ec8aac122bd4f6e,6ec8aac122bd4f6e6ec8aac122bd4f6e6ec8aac122bd4f6e.                                                                                          8分

          6ec8aac122bd4f6e,6ec8aac122bd4f6e,∴當(dāng)6ec8aac122bd4f6e時(shí),6ec8aac122bd4f6e,

          6ec8aac122bd4f6e6ec8aac122bd4f6e上遞減.                                                                                       12分

          6ec8aac122bd4f6e∴函數(shù)6ec8aac122bd4f6e的零點(diǎn)有且僅有1個(gè)     15分

           

          22.解:(1) 設(shè)6ec8aac122bd4f6e,由已知6ec8aac122bd4f6e

          6ec8aac122bd4f6e,                                        2分

          設(shè)直線PB與圓M切于點(diǎn)A,6ec8aac122bd4f6e

          6ec8aac122bd4f6e

          6ec8aac122bd4f6e6ec8aac122bd4f6e                                                 6分

          (2) 6ec8aac122bd4f6e點(diǎn) B(0,t),點(diǎn)6ec8aac122bd4f6e,                                                                7分

          進(jìn)一步可得兩條切線方程為:

          6ec8aac122bd4f6e,                                   9分

          6ec8aac122bd4f6e6ec8aac122bd4f6e,6ec8aac122bd4f6e

          6ec8aac122bd4f6e,6ec8aac122bd4f6e,                                          13分

          6ec8aac122bd4f6e,又6ec8aac122bd4f6e時(shí),6ec8aac122bd4f6e

          6ec8aac122bd4f6e6ec8aac122bd4f6e面積的最小值為6ec8aac122bd4f6e                                                                            15分

           

           


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